Dik = a. Segitiga P = 26cm & 10cm b. Segitiga R = 10cm & 6 cm d. Segitiga Q = 13cm & 6cm
Matematika
MRidwan001
Pertanyaan
Dik =
a. Segitiga P = 26cm & 10cm
b. Segitiga R = 10cm & 6 cm
d. Segitiga Q = 13cm & 6cm
a. Segitiga P = 26cm & 10cm
b. Segitiga R = 10cm & 6 cm
d. Segitiga Q = 13cm & 6cm
2 Jawaban
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1. Jawaban NikoCepiansyah
P = [tex] \sqrt{ 26^{2}- 10^{2} } [/tex]
= [tex] \sqrt{676-100} [/tex]
= [tex] \sqrt{576} [/tex]
= 24
R = [tex] \sqrt{ 10^{2}- 6^{2} } [/tex]
= [tex] \sqrt{100-36} [/tex]
= [tex] \sqrt{64} [/tex]
= 8
Q = [tex] \sqrt{ 13^{2}- 5^{2} } [/tex]
= [tex] \sqrt{169-25} [/tex]
= [tex] \sqrt{144} [/tex]
= 12
Semoga Membantu & Bermanfaat -
2. Jawaban Nerwan123
24
8
12
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