kak tolong di bantu lagi.. carilah nilai x
Matematika
anasahara
Pertanyaan
kak tolong di bantu lagi.. carilah nilai x
1 Jawaban
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1. Jawaban MuhammmadRizky
Eksponen
1||
[tex] 4^{x} [/tex] = [tex] \frac{1}{16} [/tex]
[tex] 4^{x} [/tex] = [tex] 16^{-1} [/tex]
[tex] 4^{x} [/tex] = (4²)[tex] ^{-1} [/tex]
[tex] 4^{x} [/tex] = [tex] 4^{-2} [/tex]
x = -2
2||
x^-3 = 1/27
x^-3 = 27^-1
x^-3 = (3^3)^-1
x^-3 = 3^-3
x = 3
3||
2^x = 1/16
2^x = 16^-1
2^x = (2^4)^-1
2^x = 2^-4
x = -4
4||
x^-3 = 1/-8
x^-3 = -(8^-1)
x^-3 = - (2^3^-1)
x^-3 = - (2^-3)
x = -2
5||
5^x = 1/625
5^x = 625^-1
5^x = (5^4)^-1
5^x = 5^-4
x = -4
Semoga Membantu!!!