Matematika

Pertanyaan

kak tolong di bantu lagi.. carilah nilai x
kak tolong di bantu lagi.. carilah nilai x

1 Jawaban

  • Eksponen

    1||

    [tex] 4^{x} [/tex] = [tex] \frac{1}{16} [/tex]
    [tex] 4^{x} [/tex] = [tex] 16^{-1} [/tex]
    [tex] 4^{x} [/tex] = (4²)[tex] ^{-1} [/tex]
    [tex] 4^{x} [/tex] = [tex] 4^{-2} [/tex]
                         x  = -2

    2||

    x^-3 = 1/27
    x^-3 = 27^-1
    x^-3 = (3^3)^-1
    x^-3 = 3^-3
        x  = 3


    3||

    2^x = 1/16
    2^x = 16^-1
    2^x = (2^4)^-1
    2^x = 2^-4
       x = -4


    4||

    x^-3 = 1/-8
    x^-3 = -(8^-1)
    x^-3 = - (2^3^-1)
    x^-3 = - (2^-3)
        x = -2


    5||

    5^x = 1/625
    5^x = 625^-1
    5^x = (5^4)^-1
    5^x = 5^-4
       x  = -4


    Semoga Membantu!!!