Tolong di jawab yang nomor 5
Matematika
AnnisaArdina
Pertanyaan
Tolong di jawab yang nomor 5
2 Jawaban
-
1. Jawaban newwiguna
a)
PR² = RQ² - PQ²
16² = (y + 4)² - y²
256 = y² + 8y + 16 - y²
256 = 8y + 16
8y = 256 - 16
8y = 240
y = 240 / 8
y = 30
==========================
b)
Luas segitiga = 1/2 x PQ x PR
= 1/2 x 30 cm x 16 cm
= 30 cm x 8 cm
= 240 cm² -
2. Jawaban TakumiChan
A. 16 + y + (y + 4)
= 16 + y + y + 4
= 16 + 2y + 4
= 20 = 2y
y = 20/2
y = 10
B. 1/2 x RP x PQ
= 1/2 x 16 x 10
= 8 x 10
= 80 cm²
maaf ka kalau ribet/salah :)