Matematika

Pertanyaan

Tolong di jawab yang nomor 5
Tolong di jawab yang nomor 5

2 Jawaban

  • a)
    PR² = RQ² - PQ²
    16² = (y + 4)² - y²
    256 = y² + 8y + 16 - y²
    256 = 8y + 16
    8y = 256 - 16
    8y = 240
    y = 240 / 8
    y = 30

    ==========================
    b)
    Luas segitiga = 1/2 x PQ x PR
                          = 1/2 x 30 cm x 16 cm
                          = 30 cm x 8 cm
                          = 240 cm²
  • A. 16 + y + (y + 4)
    = 16 + y + y + 4
    = 16 + 2y + 4
    = 20 = 2y
    y = 20/2
    y = 10

    B. 1/2 x RP x PQ
    = 1/2 x 16 x 10
    = 8 x 10
    = 80 cm²

    maaf ka kalau ribet/salah :)