cara menyederhanakan 3/x+1 + 3/x-1

[tex] \frac{3}{x+1} + \frac{3}{x-1} = \frac{3(x-1)+3(x+1)}{(x+1)(x-1)} \\ \\ \frac{3}{x+1} + \frac{3}{x-1} = \frac{(3x-3)+(3x+3)}{x^2-1} \\ \\ \frac{3}{x+1} + \frac{3}{x-1} = \frac{6x}{x^2-1} [/tex]