Diketahui f(2x-3)=4x-1,maka nilai f(3) adalah...

f(2x-3)= 4x-1
f (3)=....?
jawab=
f(2x-3)= 4x-1
f(a)= 4(2x+3)-1
f(a)= 8x+12-1
f(a)= 8x+11

f(3)= 8(3)+11
f(3)= 24+11
f(3)= 35