Matematika

Pertanyaan

Please jawab!1!1!1!1!
Please jawab!1!1!1!1!

1 Jawaban

  • 1.[tex] \frac{3}{ \sqrt{12} } \times \frac{ \sqrt{12} }{ \sqrt{12} } \\ = \frac{3 \sqrt{12} }{12} \\ = \frac{1}{4} \sqrt{12 } \\ = \frac{1}{4} \times 2 \sqrt{3}= \frac{2 \sqrt{3} }{4} = \frac{1}{2} \sqrt{3} [/tex]

    2.[tex] \frac{5}{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} }= \frac{5 \sqrt{15} }{15} = \frac{1}{3} \sqrt{15} [/tex]

    3.[tex] \frac{4}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ = \frac{8 - 4 \sqrt{3} }{4 - 2 \sqrt{3} + 2 \sqrt{3} - 3} \\ = \frac{8 - 4 \sqrt{3} }{4 - 3} \\ = \frac{8 - 4 \sqrt{3} }{1} = 8 - 4 \sqrt{3} [/tex]

    4.[tex] \frac{5}{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } \\ = \frac{15 + 5 \sqrt{2} }{9 + 3 \sqrt{2} - 3 \sqrt{2} - 2 } \\ = \frac{15 + 5 \sqrt{2} }{9 - 2}= \frac{15 + 5 \sqrt{2} }{7} [/tex]