Matematika

Pertanyaan

mohon jawabanya ya no 3. besok dikumpulin
mohon jawabanya ya no 3. besok dikumpulin

2 Jawaban

  • a.ac^2=ab^2+bc^2
    ac^2=12^2+9^2
    ac^2=144+81
    ac=√225
    ac=15cm

    ad^2=cd^2-ac^2
    ad^2=25^2-15^2
    ad^2=625-225
    ad=√400
    ad=20cm

    b.L∆abc=1/2×ab×bc
    =1/2×12×9
    L∆abc=54cm^2

    L∆acd=1/2×ad×ac
    =1/2×20×15
    L∆acd=150cm^2
    jadi perbandingan segitiga abc dan acd
    adalah
    54:150
    9:25
  • ^ saya anggap kuadrat yaa


    a) AC^2=CB^2+AB^2
    =12^2+9^2
    =144+81
    =225
    AC =akar 225
    =15


    AD^2=DC^2-AC^2
    =25^2-15^2
    =625-225
    =400
    AD =AKAR 400
    =20

    b) LABC =1/2.a.t
    =1/2.9.12
    =54 cm^2

    LACD =1/2.a.t
    =1/2.15.20
    =150 cm^2


    perbandingan LABC:LACD = 54:150 <=>9:25


    maaf kalau salah