Matematika

Pertanyaan

²log 20 +²log 12 - ²log 75+²log 5

1 Jawaban

  • ²log20 + ²log12 - ²log75 + ²log5
    = ²log (20 x 12 x 5)/75
    = ²log (1200/75)
    = ²log16
    = ²log2⁴
    = 4 ²log2
    = 4 (1)
    = 4

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