Tentukan [h+] dan [OH-] dalam larutan yg nilai ph nya 2+log 5

pH + pOH = 14
pOH = 14 - ( 2+log5 )
= 12-log 5
pOH = -log[OH^-]
12-log5 = -log[OH^-]
[OH^-] = 5.10^-12 M
Kw = Ka.Kb
10^-14 = Ka . 5.10^-12
Ka = [H^+] = 2 . 10^-3 M