C3H8 = -104 Kj/mol CO2 = -394 kj/mol H2O = -286 kj/mol tentukan harga H reaksi C3H8 + 5O2 -> 3CO2 + 4H20
Kimia
dianaria63
Pertanyaan
C3H8 = -104 Kj/mol
CO2 = -394 kj/mol
H2O = -286 kj/mol
tentukan harga H reaksi C3H8 + 5O2 -> 3CO2 + 4H20
CO2 = -394 kj/mol
H2O = -286 kj/mol
tentukan harga H reaksi C3H8 + 5O2 -> 3CO2 + 4H20
1 Jawaban
-
1. Jawaban ShasaMahmud
ΔH = (3(-394) + 4(-286)) - (-104 + 0)
= -1182 + (-1144) + 104
= -2222 kj/mol