persamaan garis lurus melalui titik A (-1,3) dan tegak lurus garis 2x -5y -3 = 0. adalah

2x - 5y - 3 = 0
a = 2
b = -5
c = -3

m₁ = - a/b
m₁ = - 2 /(-5)
m₁ = 2/5

tegak lurus
m₁ . m₂ = -1
2/5 . m₂ = -1
m₂ = -5/2

melalui titik A(-1, 3)
x₁ = -1
y₁ = 3

Persamaan garis
(y - y₁) = m₂(x - x₁)
(y - 3) = -5/2 (x - (-1))
-2(y - 3) = 5(x+ 1)
-2y + 6 = 5x + 5
5x + 2y = 6 - 5
5x + 2y = 1
5x + 2y - 1 = 0