diameter alas sebuah tabung setengah tingginya jika volume tabung 539cm2dan x=22/7 timggi tabung

d = t/2
r = d/2 = t/2 : 2 = t/2 x 1/2 = t/4
V = 22/7 x r x r x t
539 = 22/7 x t/4 x t/4 x t
539 x 7 x 4 x 4 = 22 t^3
60368 = 22 t^3
t^3 = 60368/22
t^3 = 2744
t = 14 cm