fanny027... tolong di cek
Matematika
IIRomeII
Pertanyaan
fanny027... tolong di cek
1 Jawaban
-
1. Jawaban fanny027
1
[tex]a. y= {sin}^{2} ( {x}^{3} + 9) \\ y' = 2 {sin}^{2 - 1} ( {x}^{3} + 9).cos( {x}^{3} + 9) .3 {x}^{2} \\ y' = 6 {x}^{2} sin( {x}^{3} + 9).cos( {x}^{3} + 9)[/tex]
[tex]b.y = sin( {x}^{2} + 2) \\ y' = cos( {x}^{2} + 5).2x \\ y' = 2x \: cos( {x}^{2} + 5)[/tex]
2
[tex]a.y = \frac{ {x}^{2} - 2x + 5 }{ {x}^{2} + 2x - 3} \\ y = \frac{u}{v} \: maka \: y' = \frac{u'v - uv'}{ {v}^{2} } \\ u' = 2x - 2 \\ v' = 2x + 2 \\ y' = \frac{(2x - 2)( {x}^{2} + 2x - 3) - ({x}^{2} - 2x + 5)(2x + 2)}{ {( {x}^{2} + 2x - 3)}^{2} } \\ agak \: bingung \: hitungnya.maaf \: gk \: bisa \: hitungin[/tex]
[tex]b.y '=10 {(2x - 3)}^{10 - 1} .2 \\ y' = 10 {(2x - 3)}^{9} .2 \\ y' = 20 {(2x - 3)}^{9} [/tex]
4. sin30°=de/mi
1/2=4/r
r=8
cos30°=sa/mi
Akar3 /2=x/8
akar3 . 8 = 2x
x= 4 akar 3
3 gk ngerti maaf
kayaknya no 3 blm diajarin
maaf kalo salah