Jika diketahui log 2=0,3010, log 3=0,4771, dan log 5=0,6989 tentukan log 180=

Kelas 10 Matematika
Bab Logaritma

log 180 = log (10 . 2 . 3²)
log 180 = log 10 + log 2 + log 3²
log 180 = 1 + 0,3010 + 2 . log 3
log 180 = 1,3010 + 2 . 0,4771
log 180 = 1,3010 + 0,9542
log 180 = 2,2552

log 180 = log ( 5 . 2^2 . 3^2)
log 180 = log 5 + log 2^2 + log 3^2
log 180 = log 5 + 2. log 2 + 2. log 3
log 180 = 0,6989 + 2. 0,3010 + 2. 0,4771
log 180 = 0,6989 + 0,602 + 0,9542
log 180 = 2,2551