dy/dx dari : y = x^2 cos x y = 3x(x^2-1) y = sin^3(2x) y = 2x/x^2-x

gunakan rumus
f(x) = U V
f'(x) = U' V + V' U

y = x^2 cos x
y' = 2x cosx - x^2 sinx

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y = 3x (x^2 - 1)

gunukan rumus bisa, atau langsung juga bisa...

y = 3x^3 - 3x
y' = 9x^2 - 3

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y = sin^3(2x)
y' = 3 cos^2 (2x) + 2 sin^3

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y = 2x / (x^2 - x)

y = x (x^2 - x) - 2x (2x - 1) / (x^2 - x)^2

[tex] \frac{x (x^2 - x) - 2x (2x - 1)}{ { (x}^{2} - x)( {x}^{2} - x) } \\ \frac{ {x}^{3} - {x - {4x}^{2} + 2x } }{ {( {x}^{2} - x)}^{2} }[/tex]
selanjutnya jabarin sendiri yaa