Tentukan persamaan garis yang melalui titik (-2, -3) dan bergradien 1/2! Tolong:(

Rumus :

[tex]y - y1 = m(x - x1)[/tex]

[tex]y - ( - 3) = \frac{1}{2} (x - ( - 2)) \\ \\ y + 3 = \frac{1}{2}(x + 2) ....( \times 2) \\ \\ 2(y + 3) = (x + 2) \\ 2y + 6 = x + 2 \\ \\ 2y - x + 4 = 0 [/tex]

y-y1=m (x-x1)
y+3=1/2(x+2)
y+3=1/2x+1....x2(agar tidak ada pecahan)
2y+6 = x+2
2y= x+2-6
2y= x-4/ -x +2y+4 = 0