pada segitiga pqr siku di q, pr+qr=25cm,dan pq =5cm hitung nilai sin p,cos p,dan tangen p.

PR²=QR²+PQ²...I
PR+QR=25........II --> PR=25-QR
PQ=5.................III

(25-QR)²=QR²+(5)²
625-50QR+QR²=QR²+25
600=50QR
12=QR

PR=25-QR
PR=25-12
PR=13

Sin(p) = QR/PR
Sin(p) = 12/13

Cos(p) = PQ/PR
Cos(p) = 5/13

Tan(p) = Sin(p)/Cos(p)
Tan(p) = 12/5