10 derajat R =....K 112 derajat F=.... °C 200 K=....°C 50 °C=....°F

*10°R = 5/4 x 10
= 50/4
= 12,5°C
10°R = 12,5 + 273
= 285,5 K
*112°F = 5/9 ( 112 - 32 )
= 5/9 ( 80 )
= 400/9
= 44,4°F
*200K = 200 - 273
= -73°C
*50°C = (9/5 • 50) - 32
= 90-32
= 58°F
Maaf kalo ada yang salah