pakai cara terimakasih

(4a^2b^-3c^-2)^3 = 4^3a^6b^-9c^-6
= 64a^6 × 1/b^9 × 1/c^6
= 64a^6
---------
b^9c^6

[tex](4a {}^{2} b {}^{ - 3} c {}^{ - 2} ) {}^{3} \\ = 4 {}^{3} a {}^{2 \times 3} b {}^{ - 3 \times 3} c {}^{ - 2 \times 3} \\ = 64a {}^{6} b {}^{ - 9} c {}^{ - 6} \\ = \frac{64a {}^{6} }{b {}^{9} c {}^{6} } [/tex]

☛️ Jadi, jawabannya C.