[tex] \frac{4 + \sqrt{3} }{ \sqrt{2} } [/tex] Toling jawab sekarang.....

[tex] \frac{4 + \sqrt{3} }{ \sqrt{2} } \\ = \frac{4 + \sqrt{3} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ = \frac{4 \sqrt{2} + \sqrt{6} }{2} [/tex]
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