tolong ya. besok di kumpulin
Matematika
rismah3
Pertanyaan
tolong ya. besok di kumpulin
2 Jawaban
-
1. Jawaban Sutr1sn0
a)
(2^3)^2 = 2^6
b)
((-5)^4)^6 = (-5)^24
c)
(3^3)^5 × (3^2)^7 = 3^15 × 3^14 = 3^29
d)
[(-8)^4 × ((-8)^3)^4]/(-8)^9
= [(-8)^4 × (-8)^12]/(-8)^9
= [(-8)^16]/(-8)^9
= (-8)^7
e)
(9^10)^9 : (9^7)^8
= 9^90 : 9^56
= 9^34
f)
(m^18)^2 : (n^6)^4
= m^36 : n^24
g)
[((-4)^3)^6 : ((-4)^2)^4]/(-4)
= [(-4)^18 : (-4)^8]/(-4)
= [(-4)^10]/(-4)
= (-4)^9
h)
[(19^2)^8 : (p^5)^11]/[19^4 × p^7]
= [19^16 : p^55]/[19^4 p^7]
= 19^12 : p^62 -
2. Jawaban zakipelajar
Mapel : Matematik
Bab : Eksponensial
Yang Dilingkari Ya
c)
ingat sifat
[tex](x ^{a} ) ^{b} = x ^{ab} [/tex]
[tex](3 ^{3} ) ^{5} \times (3 ^{2}) ^{7} [/tex]
[tex] = 3 ^{15} \times 3 ^{14} [/tex]
[tex] = 3 ^{15 + 14} [/tex]
[tex] = 3 ^{29} [/tex]
g)
((-4^3))^6 : ((-4)^2)^4 / (-4)^1
= (-4)^18 : (-4)^8 /( -4)^1
= (-4)^18-8 / (-4)^1
= (-4)^10 / (-4)^1
= (-4)^10-1
= -4^9
= -262.144