kak tolong bantuannya,, jwab pakk crnya y kak

[tex]5) \: luas \: abcd = luas \: abe \\ {(x + 2)}^{2} = \frac{1}{2} \times (x + 2)(3x - 14) \\ {x}^{2} + 4x + 4 = \frac{3 {x}^{2} - 8x - 28 }{2} \\ 2 {x}^{2} + 8x + 8 = 3 {x}^{2} - 8x - 28 \\ {x}^{2} - 16x - 36 = 0 \\ {(x - 8)}^{2} - 64 - 36 = 0 \\ {(x - 8)}^{2} = 100 \\ x = 10+ 8 = 18[/tex]
[tex]4) \: 9 + 32 + 9 + 10 + 24 + 20 + 9 + 11 + 15 + 11 = 152[/tex]
[tex]3) \: k = 150 \\ p + l = 75 \\ l + 15 + l = 75 \\ 2l = 60 \\ l = 30 \\ p = 45 \\ luas = 1350[/tex]
[tex]k = 28 \\ p + l = 14 \\ l + 2 + l = 14 \\ 2l = 12 \\ l = 6 \\ p = 8 \\ luas = 48[/tex]

No.2
Kll = 2 (P + L) , jika p = 2 + L , maka
28 = 2 (2 + L + L)
28 = 2 (2 + 2L)
28 = 4 + 4L
4L = 28 - 4
L = 24/4
L = 6 Cm <<== Lebar

karena P = 2 + L maka P = 8 cm
Sehingga
Luas = P x L
Luas = 8 x 6
Luas = 48 cm^2 <<==== Luas

No.3
Kll = 150 cm , jika P = 15 + L , maka

Kll = 2 (P + L)
150 = 2 (15 + L + L)
150 = 30 + 4L
4L = 150 - 30
L = 120/4
L = 30 cm <<=== Lebar

karena P = 15 + L , maka P = 45 cm
sehingga

Luas = P x L
Luas = 45 x 30
Luas = 1350 cm^2 <<=== Luas

No.4
Kll = 32 + 9 + 9 + 11 + 15 + 11 + 9 + 24 + 12 + 20
Kll = 152 cm

No.5

Sisi = x + 2
tinggi = 3x - 14

L.ABCD = L.ABE
S x S = 1/2 sisi x Tinggi
(x + 2) (x + 2) = 1/2 (x + 2) (3x - 14)
x^2 + 4x + 4 = 1/2 (3x^2 - 8x - 24)
2x^2 + 8x + 8 = 3x^2 - 8x - 24
3x^2 - 2x^2 - 8x - 8x - 24 - 8 = 0
x^2 - 16x - 32 = 0

gunakan rumus kecap a b c untuk mencari nilai x...
sehingga di dapat
x = 18