Teorema phytagoras Tolong donggggg

1. )

( a.) bangun trapesium
Luas = jumlah sisi sejajar x tinggi : 2
= (15+25) x 13 : 2
= 40 x 13 : 2
= 20 x 13
= 260 cm.

(B.) bangun segitiga
Luas = alas x tinggi : 2
= 30 x 17 : 2
= 15 x 17
= 255 cm.
bangun persegi panjang
Luas = panjang x lebar
= 20 x 18
= 360 cm.

Luas bangun B. = 255 + 360
= 615 cm.

2.)
(a) bangun trapesium.
keliling = jumlah seluruh sisi
= 20 + 24 + 30 + 20
= 94 cm.
(B.) bangun gabungan.
keliling = jumlah seluruh sisi.
= 5 + 19 + 5 + 7 + 23
= 59 cm.

3.) Blm tau.


maaf kalau salah

1]
a)
t^2 = 13^2 - ((25-15)/2)^2
t^2 = 13^2 - 5^2
t^2 = 169 - 25
t^2 = 144
t = V144 = 12 cm

L = [(a + b) × t]/2
L = [(25 + 15) × 12]/2
L = (40 × 12)/2
L = 480/2
L = 240 cm^2

b)
a = 6×2 + 18 = 12 + 18 = 30 cm
t^2 = 17^2 - (1/2 × a)^2
t^2 = 17^2 - (1/2 × 30)^2
t^2 = 17^2 - 15^2
t^2 = 289 - 225
t^2 = 64
t = V64
t = 8 cm

L = (1/2 × a × t) + (p × l)
L = (1/2 × 30 × 8) + (20 × 18)
L = 120 + 360
L = 480 cm^2


2]
a)
L = [(a + b) × t]/2
L = [(30 + 20) × 24]/2
L = (50 × 24)/2
L = 1200/2
L = 600 cm^2

b)
a = [V(5^2 - 4^2) × 2] + 19
a = [V(25 - 16) × 2] + 19
a = [V9 × 2] + 19
a = (3 × 2) + 19
a = 6 + 19
a = 25 cm

t^2 = a^2 - 7^2
t^2 = 25^2 - 7^2
t^2 = 625 - 49
t^2 = 576
t = V576
t = 24 cm

L = [(a + b) × t']/2 + (1/2 × a' × t)
L = [(25 + 19) × 4]/2 + (1/2 × 7 × 24)
L = [44 × 4]/2 + 84
L = 176/2 + 84
L = 88 + 84
L = 172 cm^2


3)
s^2 = (1/2 × d1)^2 + (1/2 × d2)^2
s^2 = (1/2 × 24)^2 + (1/2 × 18)^2
s^2 = 12^2 + 9^2
s^2 = 144 + 81
s^2 = 225
s = V225
s = 15 cm

K = 4 × s
K = 4 × 15
K = 60 cm