nilai x yg memenuhi persamaan[tex] 27^{2x+1} = 243^{2x-3} [/tex] adalah mohon cara kerjanya jga,

jawab


(3³)²ˣ⁺¹ = (3⁵)²ˣ⁻³

3(2x + 1) = 5(2x - 3)
6x + 3 = 10x - 15
6x -10x = - 15 - 3
- 4x = - 18
x = -18 / - 4
x = 4,5

Mapel : matematika
Bab : Eksponensial

[tex]27 ^{2x + 1} = 243 ^{2x - 3} [/tex]
[tex](3 ^{3}) ^{2x + 1} = (3 ^{5} ) ^{2x - 3} [/tex]
[tex]3 ^{6x + 3} = 3 ^{10x - 15} [/tex]
[tex]6x + 3 = 10x - 15[/tex]
[tex]3 + 15 = 10x - 6x[/tex]
[tex]18 = 4x[/tex]
[tex]18 \div 4 = x[/tex]
[tex]4,5 = x[/tex]