tentukan HP dari : a}. log(log x + 3 ) = log 2 | b}. log{ log(x-1) + log2} = log log x | c}. ³log ³log x = ³log (2-⅓ × ³log x) +2 ||||| Mohon bantuan nya yah pl

[tex]a) log(log x + 3) = log 2 \\ log x + 3 = 2 \\ log x = - 1 \\ x = \frac{1}{10} \\ b) log (log(x - 1) + log 2) = log log x \\ log 2(x - 1) = log x \\ 2(x - 1) = x \\ 2x - 2 = x \\ x = 2 \\ [/tex]

tentukan HP dari :
a}. log(log x + 3 ) = log 2
b}. log{ log(x-1) + log2} = log log x
c}. ³log ³log x = ³log (2-⅓ × ³log x) +2
Mohon bantuan nya yah plissa

JAWAB

a}. log(log x + 3 ) = log 2
⇨ log x + 3 = 2
⇨log x = -1
⇨ x = 10-¹
⇨ x = 1/10
⇨ x = 0,1

b}. log{ log(x-1) + log2} = log log x
⇨ log(x-1) + log2 = log x
⇨ log [(x-1)×2] = log x
⇨ (x-1)×2 = x
⇨ 2x - 2 = x
⇨ 2x - x = 2
⇨ x = 2

c}. ³log ³log x = ³log (2-⅓ × ³log x) + 2
⇨ ³log ³log x = ³log (2-⅓ × ³log x) + ³log 9
⇨ ³log ³log x = ³log [(2-⅓ × ³log x)×9]
⇨ ³log x = (2 - ⅓ × ³log x)×9
⇨ ³log x = 18 - 3׳log x
⇨ ³log x = 18 - ³log x³
⇨ ³log x = ³log3^18 - ³log x³
⇨ ³log x = ³log ((3^18)/x³)
⇨ x = (3^18)/x³
⇨ x⁴ = 3^18
⇨ x = 3^(18/4)
⇨ x = 3^(9/2)
⇨ x = 3⁴√3
⇨ x = 81√3