diketahui 100 ml larutan NaOH 0,002 mol , pH larutan tersebut adalah... A.12 B.10 C.9 D.7 E.4
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Pertanyaan
diketahui 100 ml larutan NaOH 0,002 mol , pH larutan tersebut adalah...
A.12
B.10
C.9
D.7
E.4
A.12
B.10
C.9
D.7
E.4
2 Jawaban
-
1. Jawaban rizkysmaga
M = n/V
= 0,002 mol/0,1 liter
= 2.10^ -2 M
NaOH → Na^+ + OH^-
2.10^-2 M ~~~~~~ 2.10^-2 M
pOH = -log[OH^-]
= -log[2.10^-2]
= 2-log 2
pH + pOH = 14
pH = 14 - ( 2-log2 )
= 12 + log 2 -
2. Jawaban Mitacusmite94
M NaOH =
Mol / V = 0.002mol /0,1 liter = 0.02 M
(OH-) = M NaOH = 0.02
pOH = - log (OH-) = - log 0.02 = 2 - log 2
pH = 14 - pOH = 14 - 2 + log 2
= 12 + log 2