diketahui(f°g)(x)=x²+4jika g (x)=x-1,f(x)=

(fog)(x)=x²+4
 g (x)=x-1
f(g(x))=x²+4
f((x-1))=x²+4

misal
p=x-1
x=p+1

f(p+1)=(p+1)^2 +4
         = p^2 + 2p + 1 + 4
         = p^2 + 2p + 5

f(x)=X^2 + 2x + 5

Mohon dikoreksi apabila salah

(fog)(x) = f(g(x)) = x² + 4

misal :
x - 1 = p
p + 1 = x

f(x - 1) = x² + 4
f(p) = (p + 1)² + 4
f(p) = p² + 2p + 1 + 4
f(p) = p² + 2p + 5
jadi f(x) = x² + 2x + 5