Matematika

Pertanyaan

tolongggg bantuuuu pakai cara pemfaktoran
tolongggg bantuuuu pakai cara pemfaktoran

1 Jawaban

  • jawab

    limit(x ->2) ( 4 - √(7x +2) ) / (x-2) =


    limit(x ->2)  (4- √(7x + 2)) (4 + √(7x +2)) /  (x-2) ( 4  + √ (7x +2) )

    limit (x->2)  (16 - 7x + 2) / (x -2) (4 + √( 7x +2 ))

    limit (x -> 2) (14 - 7x ) / (x - 2) (4  + √( 7x  + 2))

    limit (x -> 2)  -7(x - 2) / (x - 2 ). (4 + √ (7x  + 2))

    limit (x ->2)  - 7/ (4 + √(7x +2)) 

    x = 2 ---> limit = -7/ ( 4 + √(14 +2) ) =  - 7/(4 +4) 

    limit = -7/8