mohon bantuannya saya belum paham

[tex]a) \\ f(x)= \frac{4}{x-2} \\ y= \frac{4}{x-2} \\ x-2= \frac{4}{y} \\ x= \frac{4}{y} +2 \\ f^{-1}(x)= \frac{4}{x} +2 \\ \\ [/tex]

[tex]b) \\ f(x)= \frac{3x+5}{2x-4} ,2x-4 \neq 0 \\ y= \frac{3x+5}{2x-4} \\ 2xy-4y=3x+5 \\ 2xy-3x=4y+5 \\ x(2y-3)=4y+5 \\ x= \frac{4y+5}{2y-3} \\ f^{-1}(x) =\frac{4x+5}{2x-3} [/tex]