integral 3x (8x kuadrat + 6x +7) dx =

jawabannya itu diatass

∫3x(8x² + 6x + 7) dx
= 3 ∫(8x³ + 6x² + 7x) dx
= 3(8x⁴/4 + 6x³/3 + 7x²/2) + C
= 3(2x⁴ + 2x³ + 7/2 x²) + C
= 6x⁴ + 6x³ + 21/2 x² + C