Tentukan nilai x yang memenuhi |x_2|_|6+2x|?

[tex] | x - 2| - |2x + 6| = 0 \\ |x - 2| = 2 |x + 3| \\ ( {x - 2)}^{2} =2 ( {x + 3)}^{2} \\ {x}^{2} - 4x + 4 = 2( {x}^{2} + 6x + 9) \\2 {x}^{2} - {x}^{2}+ 12x + 4x + 18 - 4 = 0 \\ {x}^{2} + 16x + 14 = 0[/tex]
untuk mencari nilai x, gunakan rumus a b c..

[tex]x1.2 = \frac{ - b \frac{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{2a} \\ x1.2 = \frac{- 16 \frac{ + }{ - } \sqrt{ {16}^{2} - 4(1)(14) } }{2} \\ x1.2 = \frac{ - 16 \frac{ + }{ - } \sqrt{200} }{2} \\ x1 = \frac{ - 16 + 10 \sqrt{2} }{2} \\ x1 = - 8 + 5 \sqrt{2} \\ \\ \\ x2 = \frac{ - 16 - 10 \sqrt{2}}{2} \\ x2 = - 8 - 5 \sqrt{2} [/tex]