Diketahui segitiga DEF siku-siku di D. Panjang DF = 12 cm dan DE = 5 cm, tentukan perbandingan trigonometri sudut F

jawab
Δ DEF sik siku diD

EF² = DF² + DE²
EF = 13

sin F = 5/13
cos F = 12/13
tan F = 5/12

csc F = 13/5
sec F = 13/12
cot F = 12/5