nilai minimum fungsi f(x) = x² - 4x + 13
Matematika
KomarKj2000
Pertanyaan
nilai minimum fungsi f(x) = x² - 4x + 13
1 Jawaban
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1. Jawaban Anonyme
Kelas 10 Matematika
Bab Fungsi Kuadrat
f(x) = x² - 4x + 13
a = 1; b = -4; c = 13.
Sumbu simetri
= -b/2a
= - (-4)/(2 . 1)
= 2
f(x) = x² - 4x + 13
f(2) = 2² - 4 . 2 + 13
f(2) = 4 - 8 + 13
f(2) = 9
Nilai minimum = 9