tolongin dong lupa caranya, terimakasih sebelumnya :)

[tex] \frac{2 \sqrt{3} }{ \sqrt{3} + 2 } \\ = \frac{2 \sqrt{3} }{ \sqrt{3} + 2 } \times \frac{ \sqrt{3} - 2}{ \sqrt{3} - 2} \\ = \frac{2 \sqrt{3} ( \sqrt{3} - 2)}{3 - 4} \\ = \frac{2 \sqrt{3} ( \sqrt{3} - 2)}{ - 1} \\ = - {2 \sqrt{3} ( \sqrt{3} - 2)} \\ = - 2 \sqrt{9} + 4 \sqrt{3} \\ = - 2 \times 3 + 4 \sqrt{3} \\ = - 6 + 4 \sqrt{3} \\ = 4 \sqrt{3} - 6[/tex]

Jadi, jawabannya E.