bantu jawab kak no 3,4

[tex]bangun \: 1 \\ x = \sqrt[2]{20 {}^{2} - 12 {}^{2} } \\ x = \sqrt[2]{4 00 - 144} \\ x = \sqrt[2]{256} \\ x = 16cm[/tex]
[tex] \sqrt[2]{13 {}^{2} - 5 {}^{2} } \\ \sqrt[2]{169 - 25} \\ \sqrt[2]{144 } \\ 12 \\ \\ x = \sqrt[2]{12 {}^{2} + 35 {}^{2} } \\ x = \sqrt[2]{144 + 1225} \\ x = \sqrt[2]{1369} \\ x = 37cm[/tex]