Persamaan garis yg melalui titik a(3-5) dan (2-9) jika ax+by+c=0

a(3,-5)
b(2,-9)
m=(y2-y1)/(x2-x1)
m=-9-(-5))/(2-3)
m=-4/1
m=-4
ax+by+c=0
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y=mx+c
ambil salah satu, disini kita pake yg a
-5=-4(3)+c
-5=-12+c
-5+12=c
c=7
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y=mx+c
y=4x+7
=========
ax+by+c=0
4x+(-y)+7=0
hasil =
4x-y+7=0
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